ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:29Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
302K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
312K
∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
17K
E = mc²
det| 9 4 ; 1 10 | = 86
311K
λ = h/p
det| 5 6 ; 1 6 | = 24
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O