ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:53Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
302K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
2H₂ + O₂ → 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
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iħ ∂ψ/∂t = Ĥψ
10r² + 7r + 5 = 0