ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:39Z
iħ ∂ψ/∂t = Ĥψ
det| 9 4 ; 1 10 | = 86
259K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 12 9 ; 5 13 | = 111
159K
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
5ω² + 9ω + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
22K
∫₀^∞ e^(-α²) dα = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃