ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:25Z
10n² + 5n + 0 = 0
det| 11 2 ; 5 12 | = 122
302K
det| 7 4 ; 4 8 | = 40
312K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 8 7 ; 7 9 | = 23
d/dt [t^11] = 11t^10
Fe₂O₃ + 3CO → 2Fe + 3CO₂
311K