ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:23Z
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 4 8 ; 0 5 | = 20
259K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
257K
det| 10 2 ; 5 11 | = 100
∑_{k=1}^{n} k = n(n+1)/2
159K
PV = nRT
det| 7 4 ; 4 8 | = 40
437K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
442K
7y² + 8y + 2 = 0
det| 9 2 ; 3 10 | = 84
193K
9n² + 7n + 4 = 0
\frac{6}{6} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{1}{5} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0