ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:11Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
det| 1 4 ; 3 2 | = -10
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{y\to 0} \frac{\sin y}{y} = 1
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
iħ ∂ψ/∂t = Ĥψ
10r² + 7r + 5 = 0