ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:52Z
7φ² + 7φ + 6 = 0
det| 6 6 ; 3 7 | = 24
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
9n² + 8n + 4 = 0
det| 9 4 ; 1 10 | = 86
310K
ΔS ≥ 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
311K
E = mc²
\frac{11}{6} \sum_{i=1}^{n} i^{2}
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30