ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:31Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
211K
∫₀^∞ e^(-α²) dα = √π / 2
7y² + 6y + 1 = 0
det| 7 1 ; 7 8 | = 49
133K
det| 9 4 ; 1 10 | = 86
177K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
45K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
207K
∇²y = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃