ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:23Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
125K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
12γ² + 2γ + 2 = 0
det| 9 4 ; 1 10 | = 86
310K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
λ = h/p
∫₀^∞ e^(-β²) dβ = √π / 2
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\lim_{α\to 0} \frac{\sin α}{α} = 1
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t