ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:53Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
det| 5 3 ; 7 6 | = 9
125K
12γ² + 2γ + 2 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
311K
λ = h/p
det| 12 1 ; 5 13 | = 151
68K
∫₀^∞ e^(-x²) dx = √π / 2
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O