ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:26Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
312K
∫₀^∞ e^(-r²) dr = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
12γ² + 2γ + 2 = 0
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
68K
CH₄ + 2O₂ → CO₂ + 2H₂O
39K
det| 9 4 ; 1 10 | = 86
364K