ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 23:11Z
d/dr [r^8] = 8r^7
∫₀^∞ e^(-t²) dt = √π / 2
257K
2β² + 4β + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
159K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
270K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\lim_{α\to 0} \frac{\sin α}{α} = 1
437K
det| 11 3 ; 0 12 | = 132
det| 9 4 ; 1 10 | = 86
231K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
479K