ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 20:18Z
F = G m₁m₂ / r²
det| 3 9 ; 6 4 | = -42
\binom{n}{k} = \frac{n!}{k!(n-k)!}
159K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
270K
∂x/∂ψ = 3x
det| 7 7 ; 4 8 | = 28
437K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
442K
e^{i\pi} + 1 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
231K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2β² + 4β + 3 = 0