ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 22:30Z
\frac{7}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 5 6 ; 1 6 | = 24
312K
CaCO₃ → CaO + CO₂
det| 7 4 ; 4 8 | = 40
125K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
91K
8t² + 2t + 1 = 0
d/dφ [φ^12] = 12φ^11
∑_{k=1}^{n} k = n(n+1)/2
311K