ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:46Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
17K
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
det| 7 4 ; 4 8 | = 40
364K
det| 1 4 ; 3 2 | = -10
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