ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:11Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 9 ; 7 6 | = -33
302K
det| 9 5 ; 1 10 | = 85
312K
4β² + 5β + 0 = 0
det| 3 7 ; 2 4 | = -2
125K
d/dφ [φ^6] = 6φ^5
det| 7 1 ; 7 8 | = 49
17K
det| 5 6 ; 4 6 | = 6
310K
det| 9 4 ; 1 10 | = 86
311K
∑_{k=1}^{n} k = n(n+1)/2
264K