ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:22Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
302K
∫₀^∞ e^(-r²) dr = √π / 2
\oint_C \vec{F}\cdot d\vec{r} = 0
125K
12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
det| 7 4 ; 4 8 | = 40
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
det| 11 2 ; 5 12 | = 122
364K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K