ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:37Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
302K
∫₀^∞ e^(-z²) dz = √π / 2
312K
∫₀^∞ e^(-r²) dr = √π / 2
det| 7 4 ; 4 8 | = 40
125K
∑_{k=1}^{n} k = n(n+1)/2
91K
12γ² + 2γ + 2 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
17K
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
311K
∑_{k=1}^{n} k = n(n+1)/2
68K
\frac{6}{3} \sum_{i=1}^{n} i^{2}
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det| 11 2 ; 5 12 | = 122
6K