ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:11Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 1 4 ; 2 2 | = -6
302K
∫₀^∞ e^(-z²) dz = √π / 2
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{α\to 0} \frac{\sin α}{α} = 1
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
364K