ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:12Z
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
259K
det| 7 4 ; 4 8 | = 40
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 1 4 ; 3 2 | = -10
159K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
270K
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 4 6 ; 0 5 | = 20
193K
5ω² + 9ω + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
202K
∫₀^∞ e^(-α²) dα = √π / 2