ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:17Z
10n² + 5n + 0 = 0
det| 12 9 ; 5 13 | = 111
312K
E = mc²
det| 1 1 ; 5 2 | = -3
125K
det| 8 7 ; 7 9 | = 23
∫₀^∞ e^(-θ²) dθ = √π / 2
17K
d/dt [t^11] = 11t^10
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
311K