ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
12φ² + 6φ + 4 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
125K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
det| 9 5 ; 1 10 | = 85
311K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
ΔS ≥ 0
∫₀^∞ e^(-β²) dβ = √π / 2
e^{i\pi} + 1 = 0
det| 10 7 ; 6 11 | = 68