ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:20Z
10n² + 5n + 0 = 0
∫₀^∞ e^(-n²) dn = √π / 2
302K
∫₀^∞ e^(-z²) dz = √π / 2
312K
E = mc²
det| 7 4 ; 4 8 | = 40
125K
det| 8 7 ; 7 9 | = 23
d/dt [t^11] = 11t^10
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
311K
CH₄ + 2O₂ → CO₂ + 2H₂O
68K