ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:36Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
211K
∫₀^∞ e^(-α²) dα = √π / 2
7y² + 6y + 1 = 0
d/dz [z^11] = 11z^10
133K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
177K
E = mc²
det| 9 8 ; 3 10 | = 66
207K
∇²y = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1