ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:17Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
302K
det| 9 1 ; 7 10 | = 83
312K
∫₀^∞ e^(-r²) dr = √π / 2
d/dz [z^11] = 11z^10
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12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
CH₄ + 2O₂ → CO₂ + 2H₂O
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O