ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:35Z
10n² + 5n + 0 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
302K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
312K
E = mc²
det| 11 5 ; 0 12 | = 132
91K
det| 8 7 ; 7 9 | = 23
d/dt [t^11] = 11t^10
det| 9 4 ; 1 10 | = 86
311K
∫₀^∞ e^(-y²) dy = √π / 2
det| 4 8 ; 1 5 | = 12
det| 9 5 ; 1 10 | = 85
364K
\oint_C \vec{F}\cdot d\vec{r} = 0
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃