ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:37Z
7φ² + 7φ + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
9n² + 8n + 4 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
17K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
310K
ΔS ≥ 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
264K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30