ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:19Z
10n² + 5n + 0 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
125K
det| 8 7 ; 7 9 | = 23
d/dt [t^11] = 11t^10
∑_{k=1}^{n} k = n(n+1)/2
264K
∫₀^∞ e^(-y²) dy = √π / 2
det| 4 8 ; 1 5 | = 12
N₂ + 3H₂ ⇌ 2NH₃