ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:47Z
iħ ∂ψ/∂t = Ĥψ
AgNO₃ + NaCl → AgCl↓ + NaNO₃
259K
det| 5 9 ; 7 6 | = -33
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 4 ; 4 8 | = 40
270K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
442K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
AgNO₃ + NaCl → AgCl↓ + NaNO₃
231K
5ω² + 9ω + 6 = 0
∫₀^∞ e^(-α²) dα = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
479K