ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 22:29Z
\frac{7}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 7 4 ; 4 8 | = 40
312K
CaCO₃ → CaO + CO₂
det| 3 7 ; 2 4 | = -2
125K
8t² + 2t + 1 = 0
det| 12 1 ; 5 13 | = 151
17K
d/dφ [φ^12] = 12φ^11
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
68K
10r² + 8r + 1 = 0