ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:37Z
10n² + 5n + 0 = 0
E = mc²
det| 10 4 ; 1 11 | = 106
125K
det| 7 4 ; 4 8 | = 40
91K
det| 8 7 ; 7 9 | = 23
det| 3 6 ; 0 4 | = 12
17K
d/dt [t^11] = 11t^10
det| 2 7 ; 7 3 | = -43
311K
∑_{k=1}^{n} k = n(n+1)/2
264K
∫₀^∞ e^(-y²) dy = √π / 2