ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:13Z
∑_{k=1}^{n} k = n(n+1)/2
ops_9189.dat
11ψ² + 6ψ + 2 = 0
302K
ops_5618.csv
∇ × E = −∂B/∂t
312K
4β² + 5β + 0 = 0
spec_7724.csv
d/dt [t^3] = 3t^2
125K
ops_6000.json
det| 7 7 ; 4 8 | = 28
91K
d/dφ [φ^6] = 6φ^5
eq_4588.dat
8ψ² + 7ψ + 0 = 0
17K
spec_5737.mol
∑_{k=1}^{n} k = n(n+1)/2
310K
6n² + 3n + 0 = 0
spec_4949.csv
11φ² + 4φ + 0 = 0
311K
eq_2210.log
∂y/∂n = 5y
264K
spec_5861.eqn
∫₀^∞ e^(-ψ²) dψ = √π / 2
68K
eq_9374.mol
e^{i\pi} + 1 = 0
39K
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Σ#12
Matrix 23
Rxn set 2
Batch 4
Batch 28
Rxn set 26
Ledger /15
Eq pack 13
Matrix 11
Eq pack 1
Batch 22
Matrix 17
Ledger /21
Eq pack 25
Rxn set 20