ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:11Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
det| 7 8 ; 4 8 | = 24
125K
det| 7 1 ; 7 8 | = 49
91K
d/dφ [φ^6] = 6φ^5
det| 6 6 ; 3 7 | = 24
17K
6n² + 3n + 0 = 0
10β² + 6β + 6 = 0
det| 12 1 ; 5 13 | = 151
68K