ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:05Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
det| 9 4 ; 1 10 | = 86
91K
d/dφ [φ^6] = 6φ^5
CH₄ + 2O₂ → CO₂ + 2H₂O
17K
det| 3 1 ; 7 4 | = 5
311K
∑_{k=1}^{n} k = n(n+1)/2
68K
det| 6 6 ; 3 7 | = 24
39K