ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:51Z
7φ² + 7φ + 6 = 0
det| 10 4 ; 1 11 | = 106
302K
det| 9 4 ; 1 10 | = 86
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
91K
9n² + 8n + 4 = 0
ΔS ≥ 0
E = mc²
∫₀^∞ e^(-β²) dβ = √π / 2
39K