ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:56Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
302K
det| 4 8 ; 0 5 | = 20
312K
∇²ω = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
det| 3 7 ; 2 4 | = -2
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
311K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
2H₂ + O₂ → 2H₂O
10r² + 7r + 5 = 0
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃