ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:01Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 5 ; 1 10 | = 85
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∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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