ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:14Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 5 ; 6 10 | = 60
302K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
det| 10 4 ; 1 11 | = 106
310K
6n² + 3n + 0 = 0
det| 9 7 ; 3 10 | = 69
264K
10β² + 6β + 6 = 0
det| 4 6 ; 0 5 | = 20
68K
det| 9 4 ; 1 10 | = 86
39K