ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:13Z
∑_{k=1}^{n} k = n(n+1)/2
det| 1 2 ; 7 2 | = -12
302K
det| 3 6 ; 0 4 | = 12
312K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
det| 5 9 ; 7 6 | = -33
264K
det| 9 7 ; 3 10 | = 69
39K
∫₀^∞ e^(-β²) dβ = √π / 2
364K