ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:25Z
iħ ∂ψ/∂t = Ĥψ
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\lim_{t\to 0} \frac{\sin t}{t} = 1
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
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5ω² + 9ω + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
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