ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:34Z
N₂ + 3H₂ ⇌ 2NH₃
det| 7 4 ; 4 8 | = 40
302K
12φ² + 6φ + 4 = 0
det| 5 3 ; 2 6 | = 24
125K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 12 1 ; 5 13 | = 151
68K
det| 7 7 ; 5 8 | = 21
ΔS ≥ 0
∫₀^∞ e^(-β²) dβ = √π / 2
e^{i\pi} + 1 = 0