ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:26Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 5 ; 6 10 | = 60
302K
∫₀^∞ e^(-r²) dr = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
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12γ² + 2γ + 2 = 0
\frac{11}{6} \sum_{i=1}^{n} i^{2}
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E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K