ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:05Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 2 3 ; 5 3 | = -9
312K
∇²ω = 0
det| 9 5 ; 6 10 | = 60
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
264K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
39K
10r² + 7r + 5 = 0
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃