ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:34Z
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 9 4 ; 1 10 | = 86
270K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
437K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
442K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
231K