ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:34Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
211K
∫₀^∞ e^(-α²) dα = √π / 2
det| 5 3 ; 7 6 | = 9
311K
7y² + 6y + 1 = 0
E = mc²
det| 11 9 ; 0 12 | = 132
45K
∇²y = 0
\frac{11}{6} \sum_{i=1}^{n} i^{2}
437K
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂