ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 19:57Z
1z² + 6z + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
259K
iħ ∂ψ/∂t = Ĥψ
det| 7 4 ; 4 8 | = 40
159K
∑_{k=1}^{n} k = n(n+1)/2
270K
9α² + 7α + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
442K
F = G m₁m₂ / r²
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
202K
∑_{k=1}^{n} k = n(n+1)/2
22K