ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:50Z
10n² + 5n + 0 = 0
det| 10 4 ; 1 11 | = 106
302K
E = mc²
det| 8 7 ; 7 9 | = 23
det| 12 9 ; 5 13 | = 111
17K
∫₀^∞ e^(-n²) dn = √π / 2
310K
d/dt [t^11] = 11t^10
∑_{k=1}^{n} k = n(n+1)/2
264K
∫₀^∞ e^(-y²) dy = √π / 2
det| 9 5 ; 6 10 | = 60
68K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
39K
det| 4 8 ; 1 5 | = 12
det| 7 4 ; 4 8 | = 40
364K
∑_{k=1}^{n} k = n(n+1)/2
6K