ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:21Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
302K
det| 11 9 ; 5 12 | = 87
312K
∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
E = mc²
det| 5 6 ; 4 6 | = 6
311K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
264K
λ = h/p
det| 4 8 ; 0 5 | = 20
68K
CH₄ + 2O₂ → CO₂ + 2H₂O
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}