ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:29Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
312K
∫₀^∞ e^(-r²) dr = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
91K
12γ² + 2γ + 2 = 0
det| 7 4 ; 4 8 | = 40
17K
E = mc²
\frac{6}{3} \sum_{i=1}^{n} i^{2}
311K
λ = h/p
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O