ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:56Z
7φ² + 7φ + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
125K
9n² + 8n + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
17K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
ΔS ≥ 0
det| 5 9 ; 7 6 | = -33
311K
E = mc²
det| 1 2 ; 7 2 | = -12
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃